# Bar Bending Schedule of Column

## Bar Bending Schedule of Column

In This Article, we are going to explain to you how to find bar bending schedule of column footing

### Bar bending schedule of the column is described below:

The top view shows the length and width of the footing and column.

The length of footing is 1.5m and the width of the footing is 1.2 m.

Whereas the length and width of the column are 0.4m and 03m respectively.

To view the reinforcement detail of the footing and column we have to cut a section i.e. (Section X-X’) see in the figure below.

This is the reinforcement detail of column and footing. Here the height of the column is 5m and the thickness of the footing is 0.3m.

In this figure you will see that the

Bar no 1,2,3,4,–20mm Diameter

Bar no 5,6,7,8,–16mm Diameter

Rings= 8mm @ 150mm c/c

Firstly we have to find out cutting length of vertical bars

### Step 1:- cutting length of vertical bars.

= 5m+0.3m {-50mm cover-12mm bottom bar-10mm top bar} (see in this artical)

= 5.3 – 0.05 – 0.012-0.01

= 5.228m cutting length

Take bend = 0.3m (given)

Therefore 5.228+0.3

= 5.5288 m

### Step 2. No of bars

= 4 Bars of 16mm

= 4 Bars of 20mm

### Step 3. Unit Weight of bars

= D²/162

Here D =Diameter of Bar = 16mm

That is = 16×16/162=1.58 Kg /m

D²/162 where D = Diameter of Bar =20mm

ie = 20×20/162=2.46 kg/m

### Step 4.  Total weight of vertical Bar

= cutting length  × no of Bars × unit wt

for 16mm= 5.528×4 ×1.58 = 34.936 kg

for 20mm= 5.528 ×4×2.46 = 54.39 kg .

## FINDING OUT CUTTING LENGTH OF RINGS IN BAR BENDING SCHEDULE OF COLUMN

Clear cover of the column is 40mm

Formula to find cutting length of stirrup is = [2x(L+B)+ 20D]

Where D is the Diameter of Bar

L= Length of Column (Cover is deducted from both side)

B= Breadth of Column (Cover is deducted from both side)

Note: both side cover should be subtracted from length and breadth.

### Step1. Cutting length of bars

Here L= 0.320m , B= 0.220m, and D= 8mm or 0.008m

So put these values in the formula = [2x(L+B)+ 18D]

= [2(0.320+0.220)+20 x 0.008]

= 1.080+ 0.16

=1.24m  Cutting Length of one Ring

### Step 2: Number of Bars

= (Length / Spacing)+ 1

Here length would be taken as the vertical length of the column where the rings are placed.

So. Number of bars = (5.228/ 0.15)+1

= 34.38+1

=35.38 say 36 numbers of rings

### Step 3: the unit weight of bars

= D²/162

Here D =Diameter of Bar = 8mm

That is = 8×8/162=0.395 Kg /m

### Step 4: Total weight of Bar

= cutting length × number of Bars × unit wt

= 1.24 X 36 X 0.395

= 17.63 Kg weight.

If You Want to Calculate Excavation Quantity Of Footing Then here is the link below

For more detail visit us: RED BRICKS ACADEMY OF CIVIL ENGINEERING 