 ## Bar Bending Schedule for Slab.

In this video, we are going to explain to you that how to prepare the Bar Bending Schedule for Slab according to the drawing. after watching this video you will be able to learn the Bar Bending Schedule of Slab

In the structural Drawing, Reinforcement detail of Slab is given,

NOTE: Length of extra bar at continuous support of slab will be L/4 on both side from center of support where L is the span from center to center

For the bar bending schedule for slab, Firstly we have to find out the cutting length of the bars in placed shorter span

Here A Bars are Straight bars of Diameter 10mm and spacing= 150mm c/c

B Bars are cranked bars of diameter 10mm and spacing = 150mm c/c

C Bars are extra bars of diameter 12mm and Spacing = 150mm c/c

Step 1:-Cutting Length of Bars

1. cutting length of A bars = 3000[-(25+25)] (subtracting 25mm beam covers both side)

=2950mm or 2.95m

• Cutting length of B bars = 3000[-(25+25)] + 0.42t+0.42t

(Where T= thickness of slab, t = Thickness of slab – Top and Bottom Covers)

t = 150-(20+20) Covers top and bottom

t = 110mm

Therefore, 2.950+2x(0.42 x 0.11)

= 2.950+0.092=3.042m

• Cutting Length of C bars = C/C length

= 3-(0.125+0.125)

= 2.75m

According to drawing Cutting length of extra bar is L/4

Therefore, 2.75/4 = 0.6875 + 0.1m

= 0.7875m

Step 2:- No of Bars

1. A Bars :- opposite length(-covers)/spacing

= 10000-(25+25)/150

=9950/150= 66.33nos.

• B Bars (no. of bars of cranked bars are 1 more than straight bars as they are placed alternatively).

Therefore, 66.33+1= 64.33 nos

• C Bars Extra bars= Same as Straight bars =63.33 nos

Step 3:- the unit weight of Bar

1. for 12mm bars= D²/162

= 12×12/162=0.888Kg/m

• for 10mm bars = D2/162

= 10 x 10/162

=0.617kg/m

Step 4:-Total Weight of Bars:

1. Total weight of A bars = cutting length × No. of Bars × unit weight

= 2.95m ×63.33 × 0.617

= 115.27 kg of Bars are used

• Total Weight of B bars= cutting length × No. of Bars × unit weight

= 3.042m ×64.33 × 0.617

= 120.74 kg of Bars are used

• Total Weight of C bars= cutting length × No. of Bars × unit weight

= 0.6875m ×63.33 × 0.888

= 38.66 kg of Bars are used

Now we have to find out the cutting length of the bars placed in longer span

Here D Bars are Straight bars of Diameter 10mm and spacing= 150mm c/c

E Bars are cranked bars of diameter 10mm and spacing = 150mm c/c

F Bars are extra bars of diameter 12mm and Spacing = 150mm c/c

Step 1:-

• cutting length of D bars = 10000[-(25+25)] (subtracting 25mm beam covers both side)

=9950mm or 9.95m

• Cutting length of E bars = 10000[-(25+25)] + 0.42t + 0.42t + 042t + 0.42t

(Where T= thickness of slab, t = Thickness of slab – Top and Bottom Covers)

t = 150-(20+20) Covers top and bottom

t = 110mm

Therefore, 10+4x(0.42 x 0.11)

= 9.950+0.184=10.134m

• Cutting Length of F bars = C/C length

= 10-(0.125+0.125)

= 9.75m

According to drawing Cutting length of extra bar is L/4

Therefore, 9.75/4 = 2.4375m

Step 2:- No of Bars

• D Bars :- opposite length(-covers)/spacing

= 3000-(25+25)/150

=2950/150= 19.66nos.

• E Bars (no. of bars of cranked bars are 1 more than straight bars as they are placed alternatively).

Therefore, 19.66+1= 20.66 nos

• F Bars Extra bars= Same as Straight bars =19.66 nos

Step 3:- the unit weight of Bar

• for 12mm bars= D²/162

= 12×12/162=0.888Kg/m

• for 10mm bars = D2/162

= 10 x 10/162

=0.617kg/m

Step 4:-Total Weight of Bars:

• Total weight of D bars = cutting length × No. of Bars × unit weight

= 9.95m ×19.66 × 0.617

= 120.69 kg of Bars are used

• Total Weight of E bars= cutting length × No. of Bars × unit weight

= 10.134m ×20.66 × 0.617

= 129.18 kg of Bars are used

• Total Weight of F bars= cutting length × No. of Bars × unit weight

= 2.437m ×19.66 × 0.888

= 42.54kg of Bars are used

given below is the link for the detail of building estimation course

Red Bricks Academy of Civil Engineering