You are currently viewing Bar Bending Schedule for Footing

Bar Bending Schedule for Footing

BAR  BENDING SCHEDULE OF FOOTING.

In this video, we are going to explain to you that how to prepare the Bar Bending Schedule for footing according to the drawing. after watching this video you will be able to learn the Bar Bending Schedule of footing.

In the structural Drawing, A Top Plan of footing is given and a section is cut from either side

See the example below:-

Bar Bending Schedule for Footing

Section (x-x)

Bar Bending Schedule for Footing

Here A bars are main bars of Diameter 12mm spacing= 150mm c/c

Firstly we have to find out the cutting length of the main bar

Bar Bending Schedule for Footing

Step 1:-cutting length of A bars = 1200[-(50+50)] (subtracting 50mm covers both side)

 =1100 mm or 1.1m

Add bend length of both side  = 1.1+01+0.1

 = 1.3m

On-site we will do some deductions as if we bend a bar 90º then the bar will get stretched so we have to deduct the stretched part i.e, 2D from both sides.

Here D = Diameter of Bar = 2 x 12=24mm from both side.

=1.3-0.024-0.024

=1.252m

Step 2:- No of Bars:- opposite length(-covers)/spacing+1

                                      = 1500-(50+50)/150+1

                                      =1400/150+1=10.33 nos.

Step 3:- the unit weight of Bar = D²/162

                                            = 12×12/162=0.888Kg/m

Step 4:- Total weight = cutting length × No. of Bars × unit weight

                                      = 1.252m ×10.33 × 0.888

                                      = 11.484 kg of Bars are used

Here B bars are Distribution bars of Diameter 12mm spacing = 150mm c/c

Now  we have to find out cutting length of Distribution bars i.e. B bars

Bar Bending Schedule for Footing

Step 1:-cutting length of B bars = 1500[-(50+50)] (subtracting 50mm covers both side)

 =1400 mm or 1.4m

Add bend length of both side  = 1.4+01+0.1

 = 1.6m

Here also On-site we will do some deductions as if we bend a bar 90º then the bar will get stretched so we have to deduct the stretched part i.e, 2D from both sides.

Here D = Diameter of Bar = 2 x 12=24mm from both side.

=1.6-0.024-0.024

=1.552m

Step 2:- No of Bars:- opposite length(-covers)/spacing+1

                                      = 1200-(50+50)/150+1

                                      =1100/150+1= 7.33 nos.

Step 3:- the unit weight of Bar = D²/162

                                            = 12×12/162=0.888Kg/m

Step 4:- Total weight = cutting length × No. of Bars × unit weight

                                      = 1.552m ×7.33 × 0.888

                                      = 10.10 kg of Bars are used.

given below is the link for the detail of building estimation course

Red Bricks Academy of Civil Engineering

Leave a Reply